In triangle ABC , AngleB =90° and BD perpendicular AC . If AD =4.5cm , CD =8 CM , what is the length of BD
1) 18
2) 9
3) 6
4) 12
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Let angle ACB is x = angle CBD= 90-x = BAD = 90- x ∆ ABC,∆ ADB, and ∆BDC are similar
= BD/CD = AD/DB = 8/ CD =4/8 = CD = 8*8/4= 16
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