in triangle ABC,angleB=90° and tanA=1 then show that 2sina.cosA=1
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B=90 means it is right angle triangle
tanA=1 means prendicular and base is1
and hypotenuse is √2 by Pythagoras theorem
sin=prepend÷hyp
cos=base÷hypo
2×1÷√2×1÷√2=1
2×(1÷√2)2=1
1=1
hence proved
tanA=1 means prendicular and base is1
and hypotenuse is √2 by Pythagoras theorem
sin=prepend÷hyp
cos=base÷hypo
2×1÷√2×1÷√2=1
2×(1÷√2)2=1
1=1
hence proved
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