Question

in triangle ABC, angleB=90degrees, find the sides of the triangle if : AB=x cm, BC =(4x + 4)cm, AC = (4x +5)cm.

Answer 1

Answer:

AB= 9cm, BC= 40cm, AC= 41cm.

Step-by-step explanation:

In right-angled AABC,

AC² = AB²+ BC²

(4x + 5)² = (x)²+(4x+4)²

(16x² + 40x + 25 ) = ( x² ) + ( 16x² + 32x + 16)

x²-8x-9 = 0

(x-9)(x + 1) = 0

(x-9) = 0 or (x+1) = 0

x = 9 or x= -1

But length of the side of a triangle can not be negative.

x = 9 cm ..

AB = x = 9 cm

BC = (4x + 4)

= (4×9 +4)

= ( 36 + 4)

= 40 cm

AC = (4x + 5)

=(4×9 + 5)

= (36+5)

= 41 cm.

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