In triangle ABC, angleB = angleC and ray AN bisects exterior angle DAC. If angle DAN =70 ,find the angles of triangle ABC.
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angle B and C are of 70 and theered angle is of 40.
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angle DAN=70
AN bisects angle DAC
so, angle NAC=DAN=70
DB is a straight line, so angle DAB is 180
so, BAC+NAC+DAN=180
=>BAC+70+70=180
=>BAC=180-(70+70)
=180-140
=40
given, angle B=C,Let them be x
so, angle A+B+C=180(sum of angles of a
=> 40+x+x =180 triangle is 180)
=>2x=180-40
=>x=140/2
=70
ans-40,70,70
hope this helps
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AN bisects angle DAC
so, angle NAC=DAN=70
DB is a straight line, so angle DAB is 180
so, BAC+NAC+DAN=180
=>BAC+70+70=180
=>BAC=180-(70+70)
=180-140
=40
given, angle B=C,Let them be x
so, angle A+B+C=180(sum of angles of a
=> 40+x+x =180 triangle is 180)
=>2x=180-40
=>x=140/2
=70
ans-40,70,70
hope this helps
plz mark me
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