Question

in triangle ABC, angleC = 3angleB = 2(angleA+angleB). Find all three angles. ​

Answer 1

Answer:

Given that ∠C=3∠B=2(∠A+∠B)

Solving above equality we get

∠B=2∠A, ∠C=6∠A

But, in a triangle ΔABC we know that ∠A+∠B+∠C=180∘

∴∠A+2∠A+6∠A=180∘

9∠A=180∘

∠A=180∘9

∠A=20∘

∴∠B=2∠A=2(20∘)=40∘

∴∠C=6∠A=6(20∘)=120∘

Step-by-step explanation:

I think it's correct

Answer 2

Step-by-step explanation:

• we know that some of three angles of triangle equal to 180 degree
• therefore angle A + angle B+ angle C equal to 180 degree
• in given angle C= 2(angle A + angle B)
• angle A + angle B = (angle C)/2
• angle A + angle B + angle C= (angle C)/2 + angle C
• 180degree= 3/2(angleC)
• angleC={2/3}×180

angleC=120degree

• angle A + angle B = 180 degree -120 degree= 60 degree