Question

In triangle ABC,AP perpendicular BC, BQ perpendicular AC B-P-C,A-Q-C then prove that,triangle CPA similar triangle CQB. If AP=7,BQ=8,BC=12 then find AC.​

Answer 1

Answer:

AC= 10.5

Step-by-step explanation:

Proof: In △CPA and △CQB,

∠CPA=∠CQB=90∘ (given)

∠C=∠C (common)

By AA similarity criterion,

△CPA≅△CQB

Hence proved.

Now,

AP/BQ = AC/BC since corresponding sides are proportional.

⇒AC= AP/BQ × BC

= 7/8 × 12

= 10.5