Question

in triangle abc ap perpendicular to BC and bq is perpendicular to ac then prove that triangle CPA is similar to triangle cqb if ap is 7bq is 12 then find ac​

Answer 1

Answer:

AC=10.5 units

Step-by-step explanation:

In ∆CPA and ∆CQB, ∠CPA ≅ ∠CQB [Each angle is of measure 90°]

∠ACP ≅ ∠BCQ [Common angle]

∴ ∆CPA ~ ∆CQB [AA test of similarity]

∴ AC/BC = AP/BQ [Corresponding sides of similar triangles] ∴ AC/12 = 7/8

∴ AC = x = (12 x 7)/8

∴ AC = 10.5 Units