Question

In triangle ABC, area of triangle ABC is equal to 16 cm square. XY is parallel to BC if AB is divided in the ratio 3 is to 5 find area of triangle BXY.​

Answer 1

Step-by-step explanation:

this is solution, use similarity theorem

and u will get solution

Answer 2

In triangle ABC, area of triangle is equal to 16 cm square. XY is parallel to BC if AB is divided in ratio 3 is to 5 The area of triangle BXY is 55/8cm^2. The Step wise explaination is given below :

- It is given that,

XY is parallel to the BC and AB is divided into ratio 3:5 so,

AX:BX=3:5

- Let AX=3x, BX=5x

So,AB=AX+BX=3x+5x=8x

- Area of ΔABC/Area of ΔAXY=(AB)^2/(AX)^2

=(8x)^2/(3x)^2 =64x^2/9x^2

- The given area of ΔABC is 16cm^2.

I.e. 64x^2=16

x^2=16/64

x^2=1/4

x=1/2

- So, Ax=3/2 , Bx=5/2

AB=Ax+Bx=3/2+5/2=8/2=4

- Area ofΔAXY=9x^2. ...(proved above)

=9(1/2)^2

=9/4

- Area of quadilateral XYBC= area of ΔABC-area of ΔAXY

=16-9/4

=(64-9)/4

=55/4

- Now area of ΔBXY=(area of XYBC)/2

=(1/2)(55/4)

=55/8 cm^2