In triangle ABC at
B 90 °AB = 5cm and BC 12 cm
find the value of sin A, sec A, sin C, sec C
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Answered by
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Step-by-step explanation:
In triangle ABC at
B 90 °AB = 5cm and BC 12 cm
find the value of sin A, sec A, sin C, sec C
Answered by
0
Answer:
ok
Step-by-step explanation:
AC2=AB2+BC2
AC2= 5*2+12*2
AC2= 25+ 144
AC2= 169
AC=13cm
sinA= P/H
= 5/13
from this you can find other as well.
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