In triangle ABC, B(2,3),C(-2,6) and perimeter is 14 units then locus of centroid of triangle ABC is
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In triangle abc ,b+2,3),c(-2,6) and perimeter is 14 until then locus of centroid of triangle abc is 4051831
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Step-by-step explanation:
- Let the coordinates of the vertex be (m,n) and centroid be (h,k).
- So there is a triangle A(m,n), B(2,3),C(-2,6)
- Therefore h = m + n – 2 /3
- So m = 3h
- So k = n + 3 + 6 /3
- So n = 3k – 9
- Now base BC = √16 – 9
- = √25
- = 5
- So AC = √(3h + 2)^2 + (3k – 9 – 6)^2
- = √(3h + 2)^2 + (3k – 15)^2
- So AB = √(3h – 2)^2 + (3k – 9 – 3)^2
- = √(3h – 2)^2 + (3k – 2)^2 + (3k – 12)^2
- Perimeter = 14
- Therefore perimeter AB + BC + AC = 14
- AB + AC = 9
- So this represents an ellipse.
Reference link will be
https://brainly.in/question/52559967
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