Question

In triangle ABC ,B=60,C=40,AL-PERPANDICULAR-BC,AND AD bisects angle A ,such that LandD lie on side BC
find angle LAD?

Answer 1

Answer:

here is ur answer

Step-by-step explanation:

Angle B = 260 and angle C equals to 40 degree in triangle abc equal to angle 16 degree + 40 degree + angle equals to 180 degree angle equals to 180 degree - 100 degree equals to 18 degree it is the bisector of the angle so angle C is equal to angle dmp no angle C is equals to 18.2 equals to 40 degree now in triangle AC and equals to 19 + 40 degree + angle C is equals to 180 degree angle C A L = to 180 degree minus 30 degree equals to 50 degree angle LED equals to angle C A T - angle C A L = 250 degree minus 40 degree equal to 10 degree so angle and is equals to 10 degrees

Answer 2

Answer:

We know that the sum of all angles of a triangle is 180° Consider △ABC, we can write as ∠A + ∠B + ∠C = 180° ∠A + 60° + 40° = 180° ∠A = 80° But we know that ∠DAC bisects ∠A ∠DAC = ∠A/2 ∠DAC = 80°/2 If we apply same steps for the △ADC, we get We know that the sum of all angles of a triangle is 180° ∠ADC + ∠DCA + ∠DAC = 180° ∠ADC + 40° + 40° = 180° ∠ADC = 180° + 80° We know that exterior angle is equal to the sum of two interior opposite angles Therefore we have ∠ADC = ∠ALD + ∠LAD But here AL perpendicular to BC 100° = 90° + ∠LAD ∠LAD = 90°