Question

In triangle ABC B=90 BD is perpendicular to AC The ratio of area Triangle ADB and Triangle ABC is

Answer 1

Area of Δ ADB/Area of ΔABC  = AD/AC

Step-by-step explanation:

ΔADB & Δ ABC

∠A  = ∠A  ( common)

∠ADB = ∠ABC = 90°

=> ΔADB ≈ Δ ABC

AD/AB = BD/BC = AB/AC

=> BD  = BC * AB / AC

Area of ΔABC = (1/2) * AB * BC

Area of Δ ADB  =  (1/2) AD * BD  =  (1/2) AD * (BC * AB / AC)

= (1/2) (AD/AC) * BC * AB

=  (AD/AC) (1/2)  *AB  * BC

=  (AD/AC) Area of ΔABC

Area of Δ ADB  =   (AD/AC) Area of ΔABC

=> Area of Δ ADB/Area of ΔABC  = AD/AC

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