Question

In triangle ABC, ∠B= 90°, AB= 12cm BC= 5cm. What is the circumradius of triangle ABC ?

Answer 1

Answer: 13 cm

Step-by-step explanation:

As per the question

ABC is a triangle , in which ∠ B = 90 °

AB = 12 cm , BC = 5 cm

BC is the base of the Δ ABC

AB is the perpendicular of Δ ABC

AC is the hypotenuse of Δ ABC

We have to find AC, using Pythagoras theorem

H ² = P ² + B ²

AC ² = 12 ² + 5 ²

AC ² = 144 + 25

AC ² =  169

AC = √ 169

AC = 13

So, the hypotenuse is 13 cm

Hypotenuse is the circumradius of triangle

Answer 2

Solution :-

Given,

in triangle ∆ABC

∠B=90° , AB= 12cm, BC= 5cm

Find circumradius of triangle ∆ABC

By using Pythagoras theorem

${AC}^{2} = {AB}^{2} + {BC}^{2} \\ \\ {AC}^{2} = {(5)}^{2} + {(12)}^{2} \\ \\ {AC}^{2} = 25 \times 144 \\ \\ {AC }{ }^{2} = 169$
${AC}^{2} = \sqrt{169 } \\ \\ AC \: = \: 13cm \\ \\ BD \: = IR \: = \: crcumradius \: \\ \\ \frac{AC}{2} \:$
IR = 13/2 ,

IR = 6.5cm Ans

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@GauravSaxena01