Question

In triangle ABC,  B = 900, AC= 12 cm, BC= 6 cm, then what will be the value of AB ?​

Answer 1

Step-by-step explanation:

IF B=90° THEN

TRIANGLE ABC IS A RIGHT TRIANGLE

ACCORDING TO PYTHAGORAS THEROM

$hypotenuse ^{2} = base ^{2} + prependicular ^{2}$

$ac ^{2} = ab^{2} + {bc}^{2}$

$12^{2} = {6}^{2} + {ab}^{2}$

$144 = 36 + {ab}^{2}$

$144 - 36 = {ab}^{2}$

$108 = {ab}^{2}$

$ab = \sqrt{108}$

HOPE IS HELPFUL

PLZ MARK BRAINLIEST

Answer 2

It is given that

AB = AC = 4 cm

Using the Pythagoras theorem

BC2 = AB2 + AC2

Substituting the values

BC2 = 42 + 42

By further calculation

BC2 = 16 + 16 = 32

BC = √32 = 4√2 cm

We know that

Area of △ABC = ½ × BC × h

Substituting the values

8 = ½ × 4√2 × h

By further calculation

h = (8 × 2)/ 4√2

We can write it as

h = (2 × 2)/ √2 × √2/√2

So we get

h = 4√2/2 = 2 × √2

h = 2 × 1.41 = 2.82 cm

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