In triangle ABC b = 90° and m is the foot of the perpendicular from B to AC. If AM = 9 ,CM = 16 then bc =
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Answer:
Given:
∠ABC=90o,BD⊥AC,
BD=8 and AD=4 as in diagram.
Let ∠ACB=x
⇒∠CBD=90−x
⇒∠ABD=x
⇒∠BAD=90−x
⇒ΔABC,ΔADB and ΔBDC are similar
⇒CDBD=DBAD
⇒CD8=84
⇒CD=48×8=16cm.
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