Question

In triangle ABC, B-D-C and BD=6cm,CD=4cm.What is the ratio of A(triangleABC) to A(triangleACD) ​

Answer 1

Given :   triangle ABC, B-D-C and BD=6cm,CD=4cm

To find : ratio of A(triangleABC) to A(triangleACD) ​

Solution:

ΔABC  

Draw AM ⊥ BC    D is on BC

Hence AM ⊥ CD

Area of Δ ABC  = (1/2) BC * AM

BC = BD + CD  = 6 + 4 = 10 cm

=> Area of Δ ABC  = (1/2) *  10  * AM

=>  Area of Δ ABC  =  5 AM

Area of Δ ACD = (1/2) * CD * AM

CD = 4 cm

=> Area of Δ ACD = (1/2) * 4  * AM

=> Area of Δ ACD = 2  AM

ratio of A(triangleABC) to A(triangleACD) ​   = 5 AM   :  2 AM

=> ratio of A(triangleABC) to A(triangleACD) ​   = 5  :  2

5  :  2  is the ratio of A(triangleABC) to A(triangleACD) ​

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Answer 2

Answer:

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Step-by-step explanation:

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