Question

In triangle ABC, ∠BAC =34°, ∠ABC =90° and BC is produced to D. Find ∠ACD.

Answer 1

$\huge \mathfrak \red{AnswEr}$

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$= > acd = 124$

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❥︎$\huge\underline\bold\blue{Given}$

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• A = 34°
• B = 90°

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❥︎$\huge\underline\bold\pink{To Find}$

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• angle ACD = ?

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❥︎$\huge\underline\bold\green{SOLUTION}$

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A + B = ACD ....... property of exterior angle

$= > 34 + 90 = 124$

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$<font color = pink >$

Be Brainly ☺️...

Answer 2

Answer:

ACD = 124 degrees.

Step-by-step explanation:

Applying angle sum property in triangle ABC, we get

A + B + C = 180

34 + 90 +C = 180

C = 56 degrees.= ACB

And the angles ACD and ACB are supplementary

So, ACD + ACB = 180

     ACD + 56 = 180

    ACD = 124 degrees.