Question

in triangle ABC, BAC=90° and AD perpendicular to BC. prove that AC²=BC.DC

Answer 1

Answer:

Step-by-step explanation:

given Δabc,right <ed at 'a'

ad is prpndicular to bc

prove =ac2=bc.dc

proof

in Δabc and Δadc

<a=<adc  ------[each is 90]

<c=<c-------[common]

∴ Δabc is similar to the  Δadc -----{by a.a criteria}

ac/dc=bc/ac {bcoz correspoinding sides of the similarΔ's are equal}

∴ac2=bc.dc  

                                                         hence proved

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