Question

In triangle ABC, BC = 12, AB = 5, B = 90°. Find the value of cot 0. ​

Answer 1

Step-by-step explanation:

From figure: △ABCis a right angled triangle

AC

2

=BC

2

+AB

2

AC

2

=(5)

2

+(12)

2

AC

2

=25+144

AC

2

=169=(13)

2

or AC=13

Now from figure,

i.cosA=

AC

AB

=

13

12

ii.cscA=

BC

AC

=

5

13

iii.cosC=

AC

BC

=

13

5

iv.cscC=

AB

AC

=

12

13

Hence, proved.

Answer 2

Answer:

5/13 is the answer.

See in figure.