Question

in triangle ABC, BC =24cm and area of triangle is 120 cm
square AD perpendicular to BC .find the distance between midpoint of BD and AC?
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Answer 1

Answer:

ok mark as brainlest

Step-by-step explanation:

It shows ABC is a right angled ∆,as 24²+7²=25².Which implies AC is diagonal and <B is right angled. As D is the mid point of AC,shows BD to be the median of ∆ABC.As G is the centroid of ∆ABC,so G lies on median BD and divides in ratio 2:1.=>GD=(1/3)BD.BD being the median for a diagonal of right angled ∆,its length to be half of diagonal.=>BD=(1/2)AC=(1/2)×25=12.5cm.So GD=1/3×12.5=4.16cm.Ans.