Question

In triangle ABC, BC = 4 cm, AD = 7 cm and BE = 5 cm. Find the length of AC.​

Answer 1

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$\bold{Explanation:}$

ab=4cm

bc=9cm

ac=7cm

perimeter of triangle abc=ab+bc+ac

=(4+9+7)cm=20cm

s=(ab+bc+ac)/2=20/2=10cm

Area of triangle=androot s(s-ab)(s-bc)(s-ac)=anroot10(10-4)(10-9)(10-7)

=androot (2×5×2×3×1×3)=anroot(2×3)^2×5=6root5

Area of triangle abc=1/2×ad×bc=1/2×ad×9=6root5

=ad=(6×2×2.236)/9=2.98cm lagbhag

2 parts

ac=7cm

dc=4.5cm

ad=?

ac^2=ad^2+dc^2

7^2=ad^2+(4.5)^2

49=ad^2+20.25

49.00-20.25=ad^2

28.75=ad^2

(5.36)^2=ad^2

5.36cm lagbhag=ad