In triangle abc BC equal to a b and Angle B equal to 80 find angle A
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1
Answer:
50
Step-by-step explanation:
AB = BC
equal sides have equal angles opposite to them
angle A = angle C
80+A+ C = 180 Angle sum property
C= A
80+2 × A = 180
2× A = 180-80
A = 100× 1\2
Q= 50°
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