Question

in triangle abc, bc is produced to d, angle acd equal to 110 & ab equal to ac find angle a​

Answer 1

Given :  triangle abc, bc is produced to d,

∠acd = 110°

ab = ac

To Find : ∠a

Solution:

∠acd = 110°

∠c + ∠acd = 180°   Linear Pair

=> ∠c + 110° = 180°    

=> ∠c = 70°

ab = ac

=> ∠b = ∠c

=> ∠b = 70°

in Δabc

∠a + ∠b + ∠c  = 180°

=> ∠a + 70° + 70° = 180°

=> ∠a + 140° = 180°

=> ∠a   =  40°

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Answer 2

$\huge \mid \cal \colorbox{tan}{ANSWER} \mid$

$\tt \angle acd = 110\degree$

$\tt \angle c + \angle acd = 180 \degree$

$\tt \angle c + 110 \degree = 180 \degree$

$\tt \angle c = 70 \degree$

$\tt \: ab = ac$

$\tt \angle \: b = \angle \: c \: \: \: \\ \tt \angle \: b \: = \: 70 \degree$

$\tt \: in \: \: \triangle abc$

$\tt \angle a + \angle b \: + \angle c = 180 \degree \\ \: \tt \angle a + 70 \degree + 70 \degree = 180 \degree \\ \tt \angle a + 140 \degree \: = 180 \degree \: \: \: \: \: \: \:$

$\bf \angle a \: = 40 \degree$

#Akshi❣️