Math, asked by budumuru84, 9 months ago

in triangle ABC BC parallel to DE,AD/DB=3/5,AC=5.6cm then find the value of AE​

Answers

Answered by Anonymous
4

Answer:

x=2.1

Step-by-step explanation:

given= BC║DE, AD/DB=3/5,  AC=5.6

TO FIND= AE

SOLUTION=

AD/DB=3/5

SO, AD=3 AND DB=5

TOTAL AB= 3+5=8

NOW, AD/AB=AE/AC

  let AE= x

 3/8=x/5.6

3*5.6/8=x

21/10=x

2.1=x

Answered by EnchantedBoy
3

Answer:

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