Question

In triangle ABC ,BC parallel to DE and AD/DB=3/5 AC=5.6.Find AE.

Answer 1

Given,
AD = 3, DB = 5
So,
AB = 3+5
= 8

AD/AB = AE/AC (basic proportionality
theorum)
3/8 = AE/5.6
(3×5.6)/8 = AE
16.8/8 = AE
2.1 = AE

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Answer 2

Given in triangle ABC And triangle ADE BC || DE
Also AD/DB = 3/5,AC = 5.6

To find AE
In trinagle ABC And ADE
AD/BD = AE /EC. ----EQ 1........ ( By basic proportionality theorem....)

Doing reciprocal both sides we get
BD/AD = EC/AE

On adding 1 both sides we get,
BD + AD/AD = EC + AE/
= AB/AD = AC/AE
= 8/3 = 5.6/AE
= AE = 3 × 5.6/8
= AE = 2.1 cm Ans.....

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