Question

In triangle ABC, BD bisects angle B and is perpendicular to AC. If the length of the sides of triangle are AB=2x, BC=3y+8, AD=x and DD=2y. Find the values of x and y​

Answer 1

Step-by-step explanation:

here is your answer it is right answer

Answer 2

Answer:

∴x=4

Step-by-step explanation:

In △ABD and △CBD

BD=BD (common)

∠ADB=∠CDB (each 90  

∘

)

∠ABD=∠CDB ( BD bisect ∠B)

△ABD≅△CDB (by ASA)

⇒3x+1=5y−2 (CPCT)

⇒x=  

3

5y−3

​

    ------(1)

⇒x+1=y+2 (CPCT)

⇒x=y+1------(2)

From (1) and (2)

⇒5y−3=3(y+1)

⇒5y−3y=3+3

⇒2y=6

⇒y=3

put y=3 in (2)

x=3+1

∴x=4