Question

in triangle abc, bd is perpendicular to ac and bd= 10, ad = 8 then find ac.​

Answer 1

Answer:

Given:

∠ABC=90

o

,BD⊥AC,

BD=8 and AD=4 as in diagram.

Let ∠ACB=x

⇒∠CBD=90−x

⇒∠ABD=x

⇒∠BAD=90−x

⇒ΔABC,ΔADB and ΔBDC are similar

⇒

CD

BD

=

DB

AD

⇒

CD

8

=

8

4

⇒CD=

4

8×8

=16cm.