Question

IN TRIANGLE ABC, BE AND CD ARE ALTITUDES ON AC AND

AB RESPECTIVELY SUCH THAT BE=CD. SHOW THAT AB=AC.​

Answer 1

Answer:

here's ur answer

hope it helps u

Answer 2

Step-by-step explanation:

Given ABC is a triangle in which altitudes BD and CE to sides AC and AB are equal

In ΔADB and ΔACE

∠ADB=∠AEC=90

0

(altitudes BD and CE to sides AC and AB)

BD=CE (Given altitudes are equal)

∠BAD=∠DAB (Common angle )

ΔABD≅ΔACE [by SAS congruence]

So AB=AC

Then triangle ABC is an isosceles triangle

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