Question

In triangle abc ,BE and CF are medians show the EF parellel to CB​

Answer 1

Answer:

Step-by-step explanation:

E and F are mid point of side AC and AB respecitively

so by mid point therom we can say that line EF is pareller to side BC and
half of it.
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Answer 2

Answer:

Ques

BE and CF are two equal altitude of a triangle ABC. using RHS congruent rule, prove that the triangle ABC is isosceles?

sol-

given BE is a altitude

so, angle AEB =angle CEB=90°

ALSO, CF is a altitude

angle AFC = angle BFC =90°

triangle ABC is isosceles

In triangle BCF and triangle CBE

angle BEC =angle CEB =90°

BC=CB

FC=EB

triangle BCF similar triangle CBE

Therefore, angle FBC=angle ECB

Angle ABC = Angle ACB

AB=AC

so, triangle ABC is an isosceles triangle