Question

In triangle abc bisector of angle A and Angle B intersect at point O if angle C is equal to 70 degree find the measure of angle aob​

Answer 1

Answer:

the answer will be 70*2

Answer 2

Answer:

125°

Step-by-step explanation:

In ΔABC, ∠C= 70°.

We know that the sum of all the angles of a triangle is 180°

So, ∠A +∠B +∠C =180°

⇒ ∠A+ ∠B =180°-70°=110°. ........ (1)

Now, the bisector of ∠A and ∠B meet at point O.

Hence, ∠AOB +∠OAB +∠OBA =180°

⇒∠AOB = 180°- (∠OAB +∠OBA)

⇒∠AOB = 180° - $\frac{1}{2}$ ( ∠A +∠B )

⇒∠AOB = 180° - $\frac{1}{2} (110)$ {From equation (1)}

⇒∠AOB = 180°-55° = 125° (Answer)