Question

in triangle abc BM perpendicular to AC and CM perpendicular to a b prove that a m into AC is equal to a n into a b​

Answer 1

Answer:

Step-by-step explanation:

In Δ ABM and Δ ACN,

∠AMB = ∠ANC [Since, BM ⊥ AC and CN ⊥ AB]

∠BAM = ∠CAN [Common angle]

Hence, ∆ABM ~ ∆ACN by AA criterion for similarity

So, by corresponding sides of similar triangles we have

Answer 2

Answer:

heyyy..

pls refer attachment..

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