Question

in triangle ABC, BO and CO are angle bisector of angle ABC and angle ACB if angle A = 64 degree find angle BOC


plzz help me ​

Answer 1

Given :

In a triangle ABC, BO is an angle bisector of ∠ABC and CO is the angle bisector of ∠ACB

To Find :

m∠BOC

Solution :

From the ΔOBC,

m∠OBC + m∠OCB + m∠BOC = 180°

x° + y° + m∠BOC = 180° -----(1)

From ΔABC,

m∠A + m∠B + m∠C = 180°

64 + 2x + 2y = 180

2x + 2y = 116

x + y = 58 ------(2)

Substituting the value of (x + y) from equation (2) in the equation (1),

58° + m∠BOC = 180°

m∠BOC = 180 - 58

              = 122°

Answer 2

BOC=58 degree

Hope it helps you