In triangle ABC' C=3B=2(A+B).Find A, Band C
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Answered by
65
In a triangle ABC angle C =3 angle B = 2 (angle A+ angle B). What are the three angles?
C = 2(A+B)
C = 3B, or
2(A+B) = 3B, or
2A+2B=3B, or
B=2A.
C =2(A+2A) = 6A
A+2A+6A = 180 or 9A = 180.
Or A = 20 deg. B = 40 deg, C = 120 deg.
C = 2(A+B)
C = 3B, or
2(A+B) = 3B, or
2A+2B=3B, or
B=2A.
C =2(A+2A) = 6A
A+2A+6A = 180 or 9A = 180.
Or A = 20 deg. B = 40 deg, C = 120 deg.
Answered by
21
Answer:
We know that in a △, the sum of all the interior angles is 180
⇒∠A+∠B+∠C=180 ........(1)
Also given that,
∠C=3∠B and 3∠B=2∠A+2∠B
∠A=2
∠B Substituting values in (1), we get
2 ∠B +∠B+3∠B=180
∴∠B=40
∠A=20
∠C=120
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