Question

In triangle ABC,Cos (B+C/2)=Sin (x) then the value of x is​

Answer 1

Answer:

Step-by-step explanation:

B+C =180°-A

(180°-A)/2

Cos(90°-A/2)= sin(x)

Sin A/2=sin(x)

X=A/2

Answer 2

Answer:

given triangle ABC

we know that A+B+C = 180

on dividing the above equation by 2 on both sides, we get

A/2 +B+C/2 =90

B+C/2 =90- A/2

on taking cos ratio on both sides

cos(B+C/2) = cos(90-A/2)

cos(B+C/2) = sinA/2

from the question

sinx = sinA/2

x = A/2

therefore the value of x is A/2