Question

In triangle ABC,Cos (B+C/2)=Sin (x) then the value of x is​

Answer 1

Answer:

x = A/2

Step-by-step explanation:

In a triange ABC ,

■ angle A + angle B + angle C = 180 ( sum of anhkes of triangle )

● B + C = 180 - A

● B+C/2 = 90 - A/2

● Cos (B+C/2) = Cos (90 - A/2)

● Cos (B+C/2) = Sin (A/2)

Thus, x = A/2