Question

In triangle ABC, D and E are mid-points of
sides AB and BC respectively. Also, F is a
point in side AC so that DF is parallel to
BC.
(i) Prove that DBEF is a parallelogram.
(ii) Find the perimeter of parallelogram
DBEF, if AB = 10 cm, BC = 8.4 cm and
AC = 12 cm.​

Answer 1

Answer:

HEY GUYS MARK ME BRAINLIEST.

Step-by-step explanation:

Given: D and E are mid points of AB and BC respectively. DF∥BC

Given: D and E are mid points of AB and BC respectively. DF∥BCSince, DF∥BC D is mid point of AB

Given: D and E are mid points of AB and BC respectively. DF∥BCSince, DF∥BC D is mid point of ABBy converse of mid point theorem, F is mid point of AC and DF=

Given: D and E are mid points of AB and BC respectively. DF∥BCSince, DF∥BC D is mid point of ABBy converse of mid point theorem, F is mid point of AC and DF= 2

Given: D and E are mid points of AB and BC respectively. DF∥BCSince, DF∥BC D is mid point of ABBy converse of mid point theorem, F is mid point of AC and DF= 21

Given: D and E are mid points of AB and BC respectively. DF∥BCSince, DF∥BC D is mid point of ABBy converse of mid point theorem, F is mid point of AC and DF= 21

Given: D and E are mid points of AB and BC respectively. DF∥BCSince, DF∥BC D is mid point of ABBy converse of mid point theorem, F is mid point of AC and DF= 21 BC (I)

Given: D and E are mid points of AB and BC respectively. DF∥BCSince, DF∥BC D is mid point of ABBy converse of mid point theorem, F is mid point of AC and DF= 21 BC (I)Now, E and F are mid points of BC and AC respectively.Thus, by mid point theorem,

Given: D and E are mid points of AB and BC respectively. DF∥BCSince, DF∥BC D is mid point of ABBy converse of mid point theorem, F is mid point of AC and DF= 21 BC (I)Now, E and F are mid points of BC and AC respectively.Thus, by mid point theorem,EF∥AB or EF∥DB

Given: D and E are mid points of AB and BC respectively. DF∥BCSince, DF∥BC D is mid point of ABBy converse of mid point theorem, F is mid point of AC and DF= 21 BC (I)Now, E and F are mid points of BC and AC respectively.Thus, by mid point theorem,EF∥AB or EF∥DBSince, opposite sides are parallel to each other. Hence, DBEF is a parallelogram

Given: D and E are mid points of AB and BC respectively. DF∥BCSince, DF∥BC D is mid point of ABBy converse of mid point theorem, F is mid point of AC and DF= 21 BC (I)Now, E and F are mid points of BC and AC respectively.Thus, by mid point theorem,EF∥AB or EF∥DBSince, opposite sides are parallel to each other. Hence, DBEF is a parallelogramPerimeter of parallelogram = 2(BE+BD) (Opposite sides of parallelogram are equal)

I HOPE IT'S HELP YOU .