in triangle abc D and e are point on the side ab and ac respectively such that AD perpendicular to BC if AD = 4, AE= 8 ,DB=x-4, EC= 3x-19 , find x
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Given: In △ABC,Dand E are points on the sides AB and AC respectively such that DE || BC. AD = 4cm, AE = 8cm, DB= x-4 and EC=3x-19.
To find: x.
In△ABC. we have DE || BC
Therefon AD/DB = AE/EC [By Thale’s theorem]
4/x-4 = 8/3x-19
4(3x-19)=8(x-4)
12x-76 = 8x-32
4x = 44
x = 11
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