Question

In Triangle ABC, D and E are points AC and BC respectively such that DE || AB. If AD = 2x,
BE = 2x-1, CD=x +1 and CE = x-1, then find the value of x.
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Answer 1

Step-by-step explanation:

Given: ABC is a triangle, DE || BC, AD = x, DB = x - 2, AE = x + 2 and EC = x - 1.

To find: x

In △ABC, we have

DE || BC

Therefore [By Thale's theorem]

AD/DB = AE/EC

AD × EC × = AE × DB

x(x-1) = (x-2)(x+2)

x2 - x = x2 - 4

x = 4