Math, asked by tejveerkaurbassi, 7 months ago

In triangle ABC ,D and E are points on AB and AC such that DE is parallel to BC. If AD = 4cm .DC =8cm and AE =4.5 cm ,find the length of CE
8cm
9cm
4.5cm
4cm​

Answers

Answered by TheSUDIP
0

Step-by-step explanation:

Answer. Step-by-step explanation: GIVEN: In Δ ABC, D and E are points on AB and AC , DE || BC and AD = 2.4 cm, AE = 3.2 cm, DE = 2 cm and BE = 5 cm. Hence,BD = 3.6 cm and CE = 4.8 cm.

OR

10th

Maths

Triangles

Basic Proportionality Theorem (Thales Theorem)

In ABC, D and E are points...

MATHS

In △ABC, D and E are points on the sides AB and AC respectively such that DE || BC. If AD = 6 cm, DB = 9 cm and AE = 8 cm, find AC.

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ANSWER

The basic proportionality theorem states that if a line is drawn parallel to one side of a triangle and it intersects the other two sides at two distinct points then it divides the two sides in the same ratio.

It is given that AD=6 cm, DB=9 cm and AE=8 cm.

Using the basic proportionality theorem, we have

ABAD=ACAE=BCDE⇒ABAD=ACAE⇒156=AC8⇒6AC=15×8⇒6AC=120⇒AC=6120=20

Hence, AC=20 cm.

Answered by Slogman
0

Answer:

9cm is the answer

In triangle ABC,

DE is parallel to BC

=> AD/BD = AE/EC (Basic proportionality theorem)

Putting in values, we get

4/8 = 4.5/CE

=> CE = 9cm

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