In triangle ABC ,D and E are points on AB and AC such that DE is parallel to BC. If AD = 4cm .DC =8cm and AE =4.5 cm ,find the length of CE
8cm
9cm
4.5cm
4cm
Answers
Step-by-step explanation:
Answer. Step-by-step explanation: GIVEN: In Δ ABC, D and E are points on AB and AC , DE || BC and AD = 2.4 cm, AE = 3.2 cm, DE = 2 cm and BE = 5 cm. Hence,BD = 3.6 cm and CE = 4.8 cm.
OR
10th
Maths
Triangles
Basic Proportionality Theorem (Thales Theorem)
In ABC, D and E are points...
MATHS
In △ABC, D and E are points on the sides AB and AC respectively such that DE || BC. If AD = 6 cm, DB = 9 cm and AE = 8 cm, find AC.
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ANSWER
The basic proportionality theorem states that if a line is drawn parallel to one side of a triangle and it intersects the other two sides at two distinct points then it divides the two sides in the same ratio.
It is given that AD=6 cm, DB=9 cm and AE=8 cm.
Using the basic proportionality theorem, we have
ABAD=ACAE=BCDE⇒ABAD=ACAE⇒156=AC8⇒6AC=15×8⇒6AC=120⇒AC=6120=20
Hence, AC=20 cm.
Answer:
9cm is the answer
In triangle ABC,
DE is parallel to BC
=> AD/BD = AE/EC (Basic proportionality theorem)
Putting in values, we get
4/8 = 4.5/CE
=> CE = 9cm