In triangle abc D and E are points on the sides of AB and AC respectively such that DE//BC if AD=X DB= x-2 AE= X + 2 and EC =x-1 find the value of x.
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answer
Given: ABC is a triangle, DE || BC, AD = x, DB = x - 2, AE = x + 2 and EC = x - 1.
To find: x
In △ABC, we have
DE || BC
Therefore [By Thale's theorem]
AD/DB = AE/EC
AD × EC × = AE × DB
x(x-1) = (x-2)(x+2)
x2 - x = x2 - 4
x = 4
Answered by
0
Answer:
x=4 ans
Step-by-step explanation:
Given: ABC is a triangle, DE || BC, AD = x, DB = x - 2, AE = x + 2 and EC = x - 1.
To find: x
In △ABC, we have
DE || BC
Therefore [By Thale's theorem]
AD/DB = AE/EC
AD × EC × = AE × DB
x(x-1) = (x-2)(x+2)
x2 - x = x2 - 4
x = 4
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