in triangle ABC ,D,E,F ARE THE MIDPOINTS OF AB,BC,AC RESPECTIVELY IF DE=3CM EF=3.5CM DF=4CM LENGTHS OF THE SIDES OF TRIANGLE ABC
Answers
Answered by
0
Step-by-step explanation:
Since, D,E,F are the midpoints of BC,CA and AB,Thus
DE
AB
=
EF
BC
=
DF
AC
=2
△ABC∼△DEF
Now,
Perimeter of △DEF=DE+EF+DF
=
2
AB
+
2
BC
+
2
AC
=
2
7
+
2
8
+
2
9
=
2
7+8+9
=
2
24
=12 cm.
solution
Similar questions