Question

in triangle abc d e llBC if ad =5cm,BD=7cm andAC=18cm,find the lengthof AE.​

Answer 1

Answer:

Point D lies on AB and the point E lies on AC.

Let AE = x cm

then EC = (18 - x ) cm

AD = 5 cm

BD = 7 cm

AE/EC = AD/BD (By basic proportionality theorem )

x / 18 - x = 5 / 7

7x = 5 (18-x)

7x = 90 - 5x

7x + 5x = 90

12x = 90

x = 90/12

x = 7.5 cm

Thus, the length of AE is 7.5 cm in triangle ABC.

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Answer 2

by using basic proportionality theorem..

ad/ab=ae/ac

5/ad+bd=ae/18

5/12=ae/18

5/2=ae/3

ae=15/2

ae=7.5cm

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