Question

in triangle ABC ,D is a point on AB and E is a point on BC such that DE parallel to AC and area of triangle DBE equal to half area of triangle ABC find AD/AB​

Answer 1

in this picture your answer is

Answer 2

Step-by-step explanation:

In △ABC

DE ∥ BC

AD/BD = AE/EC Basic proportionality theorm

Basic proportionality theorm

AD = BD/2

AD/BD = 1/3

area(ABC) / area(DBE) = (AD/AB)²

area(ABC) / area(DBE) = (AD/AB)

1 - (AD/AB)

= 1 - 1 /√2

= √2 - 1 / √2

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