In triangle ABC , D is the mid point of AD. If area of Triangle ABC =10 cm².Find the area of Triangle BDE.
manideep15:
I think this question needs some clarification. How D can be midpoint of AD??
D is the mid point of BC and E is the mid point of Ad
ok
thank you
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After all this we get,
square of AD / square of ED = 5 / Area of
triangle BDE
Since , AD = 2× ED
square of (2 × ED) / square of ED = 5 / Area of
triangle BDE
4 ED*2 / ED*2 = 5 / Area of triangle BDE
4 = 5 / Area of triangle BDE
Area of triangle BDE = 5/4 cm*2
Therefore,
Area of triangle BDE = 1.25 cm*2
square of AD / square of ED = 5 / Area of
triangle BDE
Since , AD = 2× ED
square of (2 × ED) / square of ED = 5 / Area of
triangle BDE
4 ED*2 / ED*2 = 5 / Area of triangle BDE
4 = 5 / Area of triangle BDE
Area of triangle BDE = 5/4 cm*2
Therefore,
Area of triangle BDE = 1.25 cm*2
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