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In triangle ABC, D is the midpoint of BC and ED is the bisector of the angle ADB. EF is drawn parallel to BC, cutting AC in F. Prove that angle EDF is a right angle

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Answered by Sundaze77

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Given A △ABC in which D is the mid-point of side BC and ED is the bisector of ∠ADb, meeting AB in E, EF is drawn parallel to BC meeting AC in F. To proof ∠EDF is a right angle. Proof In △ADB, DE is the bisector of ∠ADB. Thus, DE and DF are the bisectors of adjacent supplementary angles ∠ADB and ∠ADCrespectively.

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In triangle ABC, D is the midpoint of BC and ED is the bisector of the angle ADB. EF is drawn parallel to BC, cutting AC in F. Prove that angle EDF is a right angle​

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In triangle ABC, D is the midpoint of BC and ED is the bisector of the angle ADB. EF is drawn parallel to BC, cutting AC in F. Prove that angle EDF is a right angle