Question

In triangle ABC, D is the midpoint of BC. If DL is perpendicular on AB and DM is perpendicular on AC such that DL = DM ,then BL=CM. (R) If two angles and the including side of one triangle are equal to the two angles and included side of anothe​

Answer 1

Step-by-step explanation:

Solution



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Its the midpoint of BCDL⊥AB and DM⊥AC such that DL=DM

Considering △BLD and △CMD as right angled triangle

So we can write it as

∠BLD=∠CMD=90∘

We know that BD=CD and DL=DM

By RHS congruence criterion

△BLD=△CMD

∠ABD=∠ACD(c.p.c.t)

Now, in ∠ABC

∠ABD=∠ACD

We know that the sides opposite to equal angles are equal so we get

AB=AC

Therefore, it is proved that AB=AC.

Answer 2

Step-by-step explanation:

another angle are also equal