IN triangle ABC, D is the midpoint of side AC such that BD =half of AC. Show
that ABC is a right angle.
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From the figure we know that D is the midpoint of the line AC
So..
AD = CD = ½ AC
BD = ½ AC. [Given]
AD = BD = CD
- Let us consider AD = BD
∠ BAD = ∠ ABD …..(1) [the angles opposite to equal sides are equal]
- Let us consider CD = BD
∠ BCD = ∠ CBD ….. (2) [the angles opposite to equal sides are equal]
in △ ABC
∠ ABC + ∠ BAC + ∠ BCA = 180 [angle sum property]
we can write
∠ ABC + ∠ BAD + ∠ BCD = 180
we get ∠ ABC + ∠ ABD + ∠ CBD = 180 [ By using equation (1) and (2)]
∠ ABC + ∠ ABC = 180o [By addition 2]
∠ABC = 180 By division ∠ABC = 90o
Therefore, ∠ABC is a right
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