Math, asked by schauhan6211, 3 months ago

IN triangle ABC, D is the midpoint of side AC such that BD =half of AC. Show
that ABC is a right angle.

Answers

Answered by Anonymous
1

Answer:

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Answered by Anonymous
24

From the figure we know that D is the midpoint of the line AC

So..

AD = CD = ½ AC

BD = ½ AC. [Given]

AD = BD = CD

  • Let us consider AD = BD

∠ BAD = ∠ ABD …..(1) [the angles opposite to equal sides are equal]

  • Let us consider CD = BD

∠ BCD = ∠ CBD ….. (2) [the angles opposite to equal sides are equal]

in △ ABC

∠ ABC + ∠ BAC + ∠ BCA = 180 [angle sum property]

we can write

∠ ABC + ∠ BAD + ∠ BCD = 180

we get ∠ ABC + ∠ ABD + ∠ CBD = 180 [ By using equation (1) and (2)]

∠ ABC + ∠ ABC = 180o [By addition 2]

∠ABC = 180 By division ∠ABC = 90o

Therefore, ∠ABC is a right

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