In triangle ABC, ∠DAE = 40°, AD=BD, and AE=EC. Find ∠BAC
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∠BAC = 110° In triangle ABC, ∠DAE = 40°, AD=BD, and AE=EC
Step-by-step explanation:
AD = BD
=> ∠DAB = ∠DBA
∠ADE = ∠DAB + ∠DBA
=> ∠ADE = 2∠DAB
AE = EC
=> ∠EAC = ∠ECA
∠AED = ∠EAC + ∠ECA
=> ∠AED = 2 ∠EAC
∠ADE + ∠AED + 40° = 180°
=> 2∠DAB + 2 ∠EAC = 140°
=> ∠DAB + ∠EAC = 70°
∠BAC = ∠DAB + 40° + ∠EAC
=> ∠BAC = ∠DAB + ∠EAC + 40°
=> ∠BAC = 70° + 40°
=> ∠BAC = 110°
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