in triangle ABC DE are line on side AC and BC respectively,when joining EA and DB, we get angle EAD=10 degree ,angle EAB=70 degree ,angle DBA=60 degree and angle DBE =20 degree,then find angle DEA
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130
make figure take a point D on AC and E on BC
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In triangle ABC, D and E are two points on the sides AB and AC respectively so that DE II BC and AD/BD = 2/3.Then the area of trapezium DECB / the area ofΔ" role="presentation" style="display: inline; font-style: normal; font-weight: normal; line-height: normal; font-size: 15px; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; word-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; padding: 0px; margin: 0px; position: relative;">ΔΔABC is equal to 1) 5/9 2) 21/25 3) 9/5 (4) 21/4
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