in triangle ABC,DE are the mid points of the sides AB and AC respectively . express de interm of BC
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given-
d is the m.p. of AB & e is the m.p. of AC
according to mid point theorem de is ll to BC and 1/2 of it
so, de= 1/2*BC
(:-:) -------------------------hope this helps--------------------------- (:-:)
d is the m.p. of AB & e is the m.p. of AC
according to mid point theorem de is ll to BC and 1/2 of it
so, de= 1/2*BC
(:-:) -------------------------hope this helps--------------------------- (:-:)
Anonymous:
:)
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According to the midpoint theorem,
The line segment joining midpoints of any two sides of a triangle is always parallel to it and also half of it.
Since, D and E are the midpoints of AB and AC
Therefore, DE || BC and also DE = 1/2 BC
The line segment joining midpoints of any two sides of a triangle is always parallel to it and also half of it.
Since, D and E are the midpoints of AB and AC
Therefore, DE || BC and also DE = 1/2 BC
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